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Solve calender Problems : 1) If January 1, 1996, was Monday, what day of the week was January 1, 1997?

Thursday Wednesday Friday Sunday View Answer

The correct option is (B)

Explanation:

The year 1996 is divisible by 4, so it is a leap year with 2 odd days.

As per the question, the first day of the year 1996 was Monday, so the first day of the year 1997 must be two days after Monday. So, it was Wednesday.

2) The first republic day of India was celebrated on January 26, 1950. What day of the week was it?

Wednesday Friday Thursday Tuesday View Answer

The correct option is (C)

Explanation:

⇒ 1600 years are divisible by 400, so the year 1600 has 0 odd days.

⇒ 300 years have 1 odd day.

⇒ 49 years = (12 leap years + 37 years)

= (12*2, odd days + 37*1, odd days)

= 24 + 37 = 61 odd days

On dividing 61 by 7, we get remainder 5, so 49 years have 5 odd days.

⇒From January 26, 1950, to January 26, 1950, we have 26 days.

26 days = 3 weeks + 5 odd days

So, total number of odd days = 1 + 5 + 5 = 11 days

⇒11 days = 1 week + 4 odd days

4 odd days represent Thursday, so it was Thursday on January 26, 1950.

3) On February 5, 1998, it was Thursday. The day of the week on February 5, 1997, was

Wednesday Monday Friday Sunday View Answer

The correct option is (A)

Explanation:

1997 was an ordinary year, it had 1 odd day. So, the day on February 5, 1998, would be one day beyond the day on February 5, 1997.

∴ Thursday on February 5, 1998, would be one day beyond the day on February 5, 1997, so the day on February 5, 1997, was Wednesday.

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4) Today is Wednesday, after 68 days, it will be

Friday Sunday Monday Thursday View Answer

The correct option is (C)

Explanation:

Each day of a week is repeated after 7 days, so after 70 days, it will be Wednesday.

Therefore, after 68 days, it will be Monday.

5) What was the day of the week on June 17, 1991?

Tuesday Wednesday Friday Monday View Answer

The Correct answer; option (D)

Explanation:

June 17, 1991 = (1990 years + period from 01.01.1991 to 17.06.91)

⇒Odd days in 1600 years = 0

⇒Odd days in the next 300 years = 15 odd days (2 week + 1 odd day) = 1 odd day

90 years have 22 leap years + 68 ordinary years.

⇒Number of odd days in 90 years = 22*2 + 68*1 = 112 odd days (16 weeks + 0 odd day) = 0 odd day

Number of odd days from 01.01.91 to 17.06.91= Jan. (31) + Feb. (28) + March (31) + April (30) + May (31) + June (17) = 168 days

⇒168 days = 24 weeks + 0 odd days

Total number of odd days = 0 + 1 + 0+ 0 = 1 odd day

1 odd day represents Monday, so the given day was Monday.

6) Which of the following years is not a leap year?

800 700 1600 2000 View Answer

The Correct answer; option (B)

Explanation:

A century divisible by 400 is a leap year. The years 800, 1600 and 2000 are divisible by 400, so they are leap years.

The year 700 is not divisible by 400, so it is not a leap year.

7) How many days are there in y weeks y days?

8y 8y^{2} 16y 21y View Answer

The Correct answer; option (A)

Explanation:

There are 7 days in a week, so y weeks will contain 7y days.

∴The required number of days = 7y + y days = 8y days

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8) The day on 5^{th} April of a year will be the same day on 5^{th} of which month of the same year?

5^{th} July 5^{th} August 5^{th} June 5^{th} October View Answer

The Correct answer; option (A)

Explanation:

April & July for all years have the same calendar. So, a day on any date of April will be the same day on the corresponding date in July.

∴The same day will fall on 5th July of the same year.

9) It was Saturday on January 1, 2005. Find the day of the week on January 1, 2010.

Tuesday Friday Wednesday Sunday View Answer

The Correct answer; option (B)

Explanation:

On December 31, 2004, it was Friday.

Number of odd days from the year 2005 to the year 2009 = 1+1+1+2(leap year) +1 = 6 odd days

∴On December 31, 2009, it was Thursday, so on January 1, 2010, it was Friday.

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10) If it was Wednesday on March 1, 2006, which day was it on March 1, 2002?

Tuesday Friday Monday Sunday View Answer

The Correct answer; option (B)

Explanation:

Total number of odd days between the years 2002 and 2006 =

(2006 – 2002) + 1 = 5 odd days. The year 2004 is a leap year, it has two odd days. So, one extra odd day is added.

So, if it was Wednesday on March 1, 2006, it would be (Wednesday – 5) Friday on March 1, 2002.