0% 0 votes, 0 avg 9 See time here Aptitude Quizzes Aptitude QuizTotal Questions: 100Time: 180 minutes 1 / 100 Category: Partnership QuestionsA, B, and C invest 63000, 56000, and 84000 respectively to start a business. After one year, the profit is distributed in the ratio of their investments. If C’s share of profit is Rs.54000, find the total profit earned. 135000 130500 135030 145000 Explanation:Let the total profit = xThe ratio of investment = 63000: 56000: 84000=63:56:84On dividing by 7, we get 9:8:12Now, sum of the ratios = 29Apply formula:C’s share = (C’s ratio/ sum of all three ratios)* total profitC’s share = (12/29) * x = 54000x= (54000*29)/12x= 130500Hence, the total profit = 1305002 / 100 Category: Partnership QuestionsA and B entered into partnership with capitals in the ratio 4 : 5. After 3 months, A withdrew of his capital and B withdrew of his capital. The gain at the end of 10 months was Rs. 760. A's share in this profit is: Rs. 360 Rs. 330 Rs. 340 Rs. 320 Explanation:A : B =4x x 3 +4x -1x 4xx 7:5x x 3 +5x -1x 5xx 745= (12x + 21x) : (15x + 28x)= 33x :43x= 33 : 43. A's share = Rs.760 x33= Rs. 330.763 / 100 Category: Partnership QuestionsTwo partners invest Rs.125000 and Rs. 85000 respectively in a business and agree that 60% of the profit should be divided equally between them and the remaining profit is to be treated as interest on capital. One partner gets 300 more than the other. Find the total profit made in the business. 3739.50 3749.50 2375.60 3937.50 Explanation:The investment ratio is: 125000: 85000= 125:85On dividing both sides by 5, we get 25:17ATQ, 60% is divided equally, and the remaining 40% is shared on the investment ratio basis.The difference between 40% of their profit is 300.Let a number xi.e., 25* x *(40/100) – 17*x *(40/100) = 300(1000/100)* x – (680/100)*x =30010x – (34/5)*x = 30050x-34x = 150016x =1500x= 93.75Total profit means sum of ratios = 25x+17x = 42x42*93.75 = 3937.504 / 100 Category: Boats and Stream QuestionsA man takes twice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of the boat (in still water) and the stream is: 2 : 1 3 : 2 3 : 1 3 : 4 Explanation:Let man's rate upstream be x kmph.Then, his rate downstream = 2x kmph. (Speed in still water) : (Speed of stream) =2x + x:2x - x22 =3x:x22= 3 : 1.5 / 100 Category: Clock QuestionsAt what time, in minutes, between 3 o'clock and 4 o'clock, both the needles will coincide each other? 13(4/11)" 5(1/11)" 12(4/11)" 16(4/11)" Explanation:At 3 o'clock, the minute hand is 15 min. spaces apart from the hour hand.To be coincident, it must gain 15 min. spaces.55 min. are gained in 60 min.15 min. are gained in60x 15min=164min.5511 The hands are coincident at 164min. past 3.116 / 100 Category: Percentage QuestionsIn an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was: 2700 2800 3000 2600 Explanation:Number of valid votes = 80% of 7500 = 6000. Valid votes polled by other candidate = 45% of 6000=45x 6000= 2700.1007 / 100 Category: Percentage QuestionsThree candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get? 90% 57% 65% 60% Explanation:Total number of votes polled = (1136 + 7636 + 11628) = 20400. Required percentage =11628x 100% = 57%.204008 / 100 Category: Ages QuestionsA person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present? 40 years 44 years 36 years 32 years Explanation:Let the mother's present age be x years.Then, the person's present age =2xyears.52x + 8=1(x + 8)52 2(2x + 40) = 5(x + 8) x = 40.9 / 100 Category: Compound Interest QuestionsRamesh borrowed Rs. 3600 at a certain rate of interest C.I. and the sum grows to Rs. 4624 in 2 years. What is the rate of interest? 15.3% 14.3% 12.3% 13.3% Explanation:Principal = Rs. 3600Amount = Rs. 4624t = 2 yearsWe have;10 / 100 Category: Ages QuestionsThe present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years). 9, 25, 35 8, 20, 28 16, 28, 36 20, 35, 45 Explanation:Let their present ages be 4x, 7x and 9x years respectively.Then, (4x - 8) + (7x - 8) + (9x - 8) = 56 20x = 80 x = 4. Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.11 / 100 Category: Height and Distance QuestionsA telegraph post is bent at a point above the ground. Its top just touches the ground at a distance of 8√3 m from its foot and makes an angle of 30° with the horizontal. The height (in metre) of the post is 28 16 24 20 12 / 100 Category: Compound Interest QuestionsThe compound interest on a certain sum for 2 years at 10% per annum is Rs. 525. The simple interest on the same sum for double the time at half the rate percent per annum is: Rs. 800 Rs. 400 Rs. 600 Rs. 500 Explanation:Let the sum be Rs. P.Then,P1 +102- P= 525100P112- 1= 52510 P =525 x 100= 2500.21 Sum = Rs . 2500.So, S.I. = Rs.2500 x 5 x 4= Rs. 50010013 / 100 Category: Ages QuestionsMy brother, Ravi is 3 years elder to me. My father’s age was 28 years when my sister, Neha was born, and my mother’s age was 26 years when I was born. If Neha’s age was 4 years when Ravi was born, what was the age of my father when Ravi was born? 32 years 34 years 33 years 35 years Explanation:Let my age =xThenRavi’s age =x+3Mother’s age =x+26Neha?s age =(x+3) +4=x+7Father’s age =(x+7) +28=x+35So, the age of the father at the time of Ravi was born=x+35-(x+3) =32 years14 / 100 Category: Boats and Stream QuestionsThe speed of the stream is 5km/hr. A boat goes 10 km upstream and returns back to the starting point in 50 minutes. Find the velocity of the boat in still water. 35km/hr 20km/hr 30km/hr 25km/hr Answer with the Explanation:Let the speed or velocity of the boat in still water is x km/hrAnd the Speed of the stream = 5km/hrSo, the speed of the boat along the stream = (x+5) km/hr.The velocity of the boat against the stream = (x-5) km/hr.Note: Time = Distance / SpeedSo, [10/ (x+5)] + [10/ (x-5)] = (50/60) hrs.Note: go through the given options to get the answer quickly or solve the equation as follows:Or, [10 (x-5+x+5)]/ [(x+5) (x-5)] = 5/6Or, 20x * 6 = 5(x2-52)Or, 120x = 5(x2-25)Or, x2-25-24x=0Or, x2-24x-25=0Or, x2-25x+x-25=0Or, x(x-25) +1(x-25) =0Now, we can say(X-25)(x+1)= 0Or, x=25, x= -1 (speed can’t be -ve).So, the velocity of the boat in still water is 25 km/hr.15 / 100 Category: Compound Interest QuestionsOn a certain sum of money the compound interest Rs. 318 is earned in 2 years. If the rate of interest is 12%, what is the principal amount? Rs. 1250 Rs.1300 Rs.1200 Rs.1150 Explanation:We have;C.I. = Rs. 318r = 12%t = 2 years16 / 100 Category: Boats and Stream QuestionsA boat running downstream covers a distance of 16 km in 2 hours while for covering the same distance upstream, it takes 4 hours. What is the speed of the boat in still water? 8 km/hr 4 km/hr 6 km/hr 10 km/hr Explanation:Rate downstream =16kmph = 8 kmph.2Rate upstream =16kmph = 4 kmph.4 Speed in still water =1(8 + 4) kmph = 6 kmph.217 / 100 Category: Partnership QuestionsRamesh and Suresh enter into a partnership with capitals in the ratio of 10:12. At the end of 8 months, Ramesh withdraws. If they receive profits in the ratio of 10:18. Find how long Suresh’s capital was used. 12 months 8 months 7 months 10 months Explanation:Let the capital of Ramesh (C1) =10And the capital of Suresh is (C2) = 12Time period spend by Ramesh (T1) = 8 monthsLet, time period spend by Suresh (T2) = x monthsThe ratio of their profit (p1:p2) is 10: 18Apply formula: (C1 * T1)/ (C2 * T2) = p1/p2(10 * 8)/ (12*x) = (10/18)(80/12x) = (5/9)20/3x = 5/9180 = 15xHence, x=12 months18 / 100 Category: Number QuestionsWhich one of the following numbers is exactly divisible by 11? 315624 415624 235641 245642 Explanation:(4 + 5 + 2) - (1 + 6 + 3) = 1, not divisible by 11.(2 + 6 + 4) - (4 + 5 + 2) = 1, not divisible by 11.(4 + 6 + 1) - (2 + 5 + 3) = 1, not divisible by 11.(4 + 6 + 1) - (2 + 5 + 4) = 0, So, 415624 is divisible by 11.19 / 100 Category: Average QuestionsA car owner buys petrol at Rs.7.50, Rs. 8 and Rs. 8.50 per litre for three successive years. What approximately is the average cost per litre of petrol if he spends Rs. 4000 each year? Rs. 7.98 Rs. 7.88 Rs. 7.95 Rs. 7.89 Explanation:Total quantity of petrolconsumed in 3 years=4000+4000+4000 litres7.5088.50= 40002+1+2 litres15817=76700 litres51Total amount spent = Rs. (3 x 4000) = Rs. 12000. Average cost = Rs.12000 x 51= Rs.6120 = Rs. 7.987670076720 / 100 Category: Partnership QuestionsX and Y enter into a partnership for a year. X invests Rs. 6000, and Y invests Rs. 8000. After 4 months, they admit Z, who invests Rs. 9000. If Y withdraws his contribution after 6 months, how would they share a profit of Rs 1000 at the end of the year? 400, 300, 300 100, 600,300 375, 250, 375 350, 300, 350 Explanation:X’s capital be C1 = 6000Y’s capital be C2 = 8000Z’s capital be C3 = 9000X’s time be T1 = 12 monthsY’s time be T2 = 6 monthsZ’s time be T3 = 8 monthsProfit = 1000The profit will be divided in the ratio:-(C1 * T1): (C2 * T2): (C3 * T3)(6000*12): (8000*6): (9000*8)i.e., 72000: 48000: 72000Or, 72:48:72Divide the whole equation by 24.The ratio will be 3: 2: 3Sum of the ratios will be 3+2+3= 8Apply formula:X’s share = (X’s ratio/ sum of all three ratios)* total profitHence, X’s share is (3/8) * 10000 = 375X’s and Z’s share are equal in ratio, so Z’s share =375Y’s share = 1000 – (A + B)’s share= 1000 – 750 = 25021 / 100 Category: Height and Distance QuestionsAn observer 1.6 m tall is 20 square root 3 away from a tower. The angle of elevation from his eye to the top of the tower is 30°. The height of the tower is: 25.6 m 21.6 m 23.2 m 24.4 m Explanation:Let AB be the observer and CD be the tower.Draw BE CD.Then, CE = AB = 1.6 m,BE = AC = 203 m.DE= tan 30° =1BE3 DE =203m = 20 m.3 CD = CE + DE = (1.6 + 20) m = 21.6 m.22 / 100 Category: Ages QuestionsThe sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be: 12 years 14 years 18 years 20 years Explanation:Let the present ages of son and father be x and (60 -x) years respectively.Then, (60 - x) - 6 = 5(x - 6) 54 - x = 5x - 30 6x = 84 x = 14. Son's age after 6 years = (x+ 6) = 20 years..23 / 100 Category: Compound Interest QuestionsIn how many years the compound interest on Rs. 10000 at the rate of 10% will be Rs. 2100 ? 3 years 1.5 years 2 years 2.5 years Explanation:Principal = Rs. 10000r = 10%C.I. = Rs. 210024 / 100 Category: Average QuestionsFour years ago, the average age of A and B was 20 years. If today average age of A, B and C is 25 years, what will be age of C after 7 years? 32 years 34 years 36 years 38 years Explanation:Total age of A and B four years ago = 20 ∗ 2 = 40 yearsPresent total age of A and B would be = 40 + 4∗2 = 48 yearsPresent total age of A, B and C is = 25 ∗ 3 = 75 years∴ Present age of C would be = 75 – 48 = 27 yearsAge of C after 7 years = 27 + 7 = 34 years25 / 100 Category: Partnership QuestionsA, B, and C enter into a partnership. A invests one-fourth of the capital for one-fourth of the time. B invests one-fifth of the capital for half of the time. C contributes the remaining capital for the whole time. How should they divide a profit of Rs 1140? 100, 160, 880 150, 540, 870 100, 160, 860 Explanation:Let capital is 1unit, and time is 1unitApply the formula to calculate the profit ratio(C1 * T1): (C2 * T2): (C3 * T3)(¼ * ¼): (1/5 * ½): ((1-(1/4 + 1/5))*1)i.e., (1/16): (1/10): (1- (5+4)/20)1/16: 1/10: 11/20To calculate the investment ratio, take LCM of the denominators and multiply with each fraction.LCM of 16, 10, and 20 is 80Now, (80/16): (80/10): ((11*80)/20)We get the investment ratio: 5:8:44Total profit is 1140Apply formula:A’s share = (A’s ratio/ sum of all three ratios)* total profitA’s share = (5/57)* 1140 = 100B’s share = (8/57)*1140= 160C’s share = 1140 – (100+160) = 88026 / 100 Category: Average QuestionsWhat is the average of first five multiples of 12? 24 60 12 36 Explanation:Average = 12∗(1+2+3+4+5) ∗ = 12 ∗ 15∗ = 12 ∗ 3= 36Try to solve more problems on average.27 / 100 Category: Number QuestionsThe sum of first five prime numbers is: 11 28 18 26 Explanation:Required sum = (2 + 3 + 5 + 7 + 11) = 28.Note: 1 is not a prime number.Definition: A prime number (or a prime) is a natural number that has exactly two distinct natural number divisors: 1 and itself.28 / 100 Category: Compound Interest QuestionsIf the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, what is the compound interest on the same at the same rate and for the same time? Rs. 51.25 Rs. 60 Rs. 54 Rs. 54.25 Explanation:Sum = Rs.50 x 100= Rs. 500.2 x 5Amount= Rs.500 x1 +52100= Rs.500 x21x212020= Rs. 551.25 C.I. = Rs. (551.25 - 500) = Rs. 51.2529 / 100 Category: Ages QuestionsAt present, the ratio between the ages of Arun and Deepak is 4 : 3. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present ? 12 years 17 years 21 years 15 years Explanation:Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,4x + 6 = 26 4x = 20x = 5. Deepak's age = 3x = 15 years.30 / 100 Category: Boats and Stream QuestionsThe speed of a boat in still water in 15 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 12 minutes is: 1.2 km 2.4 km 3.6 km 1.8 km Explanation:Speed downstream = (15 + 3) kmph = 18 kmph.Distance travelled =18 x12km = 3.6 km.6031 / 100 Category: Percentage QuestionsIf the price of sugar increases by 10%, by what percentage a housewife should reduce the consumption of sugar so that expense is not increased? 10% 5.5% 7.1% 9.1% Explanation:Apply formula:=x = 10%Percentage decrease in consumption =32 / 100 Category: Calender QuestionsHow many days are there in x weeks x days? 8x 14x 7x 7 Explanation:x weeks x days = (7x + x) days = 8x days.33 / 100 Category: Calender QuestionsWhich of the following years is not a leap year? 1600 800 2000 700 A century divisible by 400 is a leap year. The years 800, 1600 and 2000 are divisible by 400, so they are leap years.The year 700 is not divisible by 400, so it is not a leap year34 / 100 Category: Percentage QuestionsGauri went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items? Rs. 20 Rs. 19.70 Rs. 15.70 Rs. 15 Explanation:Let the amount taxable purchases be Rs. x.Then, 6% of x =30100 x =30x100 = 5.1006 Cost of tax free items = Rs. [25 - (5 + 0.30)] = Rs. 19.7035 / 100 Category: Number Questions(?) - 19657 - 33994 = 9999 59640 53760 63650 61560 Explanation: 19657 Let x - 53651 = 9999 33994 Then, x = 9999 + 53651 = 63650 ----- 5365136 / 100 Category: Boats and Stream QuestionsA boat covers 6 km upstream and returns back to the starting point in 2 hours. If the flow of the stream is 4 km/hr, what is the speed of the boat in still water? 6km/hr 8km/hr 5km/hr 7.3 km/hr Answer with the Explanation:ATQ, distance covered in upstream = 6 km, and the same distance is covered in downstreamNow, apply the formulaTime = Distance/ speedLet the upstream speed = y km/hr, and the downstream speed = x km/hr.Or, (6/x) + (6/y) = 2Or, speed in upstream = speed of boat in still water – speed of streamOr, speed in downstream = speed of boat in still water + speed of streamLet Sb= speed of boat in still water6/ (Sb + 4) + 6/ (Sb – 4) = 2[6* (Sb – 4) + 6* (Sb + 4)]/ [Sb2 – 16] = 2[6Sb-24 + 6Sb+24]/ [Sb2 – 16] = 212Sb = 2Sb2 – 322Sb2-12Sb-32=0Sb2– 6Sb-16=0Sb2 – 8Sb+2S-16 =0Sb (Sb-8) +2(Sb – 8)=0(Sb-8)(Sb+2)=0Sb-8=0, Sb+2 = 0Sb= 8, Sb=-2Since, the speed can’t be -veHence, Speed of boat in still water is 8 km/hr.37 / 100 Category: Average QuestionsIn Arun's opinion, his weight is greater than 65 kg but less than 72 kg. His brother doest not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Arun? 67 kg. 69 kg. 63 kg. 72 kg. Explanation:Let Arun's weight by X kg.According to Arun, 65 < X < 72According to Arun's brother, 60 < X < 70.According to Arun's mother, X <= 68The values satisfying all the above conditions are 66, 67 and 68. Required average =66 + 67 + 68=201= 67 kg.3338 / 100 Category: Partnership QuestionsMahesh and Suresh rent a pasture for 12 months. Mahesh puts in 200 cows for 8 months. How many cows can Suresh put in the pasture for the remaining 4 months if he pays 1(1/2) as much as Mahesh? 300 cows 450 cows 520 cows 600 cows Explanation:Let Mahesh’s cow (C1) = 200 cows, and time spend T1 = 8 monthsSuresh’s cow (C2) = y cows, and time spend T2 = 4 monthsLet the profit of Mahesh = xThen the profit of Suresh = 1(1/2)*xApply profit ratio formula:(C1 * T1)/ (C2 * T2) = p1/p2(200 * 8)/ (y*4) = (x/ (3x/2))400/y = 2x/3x400/y = 2/3y = (400*3)/2y= 600Hence, Suresh can put 600 cows for the remaining 4 months.39 / 100 Category: Number QuestionsIf the number 517*324 is completely divisible by 3, then the smallest whole number in the place of * will be: 1 2 0 3 Explanation:Sum of digits = (5 + 1 + 7 + x + 3 + 2 + 4) = (22 + x), which must be divisible by 3. x = 2.40 / 100 Category: Partnership QuestionsA starts business with Rs. 3500 and after 5 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B's contribution in the capital? Rs. 8000 Rs. 8500 Rs. 9000 Rs. 7500 Explanation:Let B's capital be Rs. x.Then,3500 x 12=27x3 14x = 126000 x = 9000.41 / 100 Category: Boats and Stream QuestionsA boat covers 12 km upstream and 18km downstream in 3 hours while it covers 36km upstream and 24 km downstream in 6[1/2] hours, what is the velocity of the stream? 1.5km/hr 2.5km/hr 3km/hr 2km/hr Answer with the Explanation:ATQ, Distance in upstream =12kmDistance in downstream = 18 kmLet the speed in upstream = y km/hrAnd the speed in downstream = x km/hrNow, apply the formula.Time = Distance/ speedOr, (18/x) + (12/y) = 3………….. (i)And (24/x) + (36/y) = 13/2……… (ii)Now, multiply equation i by 3 to equate both equations.(54/x) + (36/y) = 9………… (iii)(24/x) + (36/y) = 13/2…….. (iv)Now subtract equation iii by iv.30/x = 9-13/2Or, 30/x = 5/2Or, 5x=60, i.e., x = 12Now, put the value of x in equation i(18/12) + (12/y) = 3Or, 3/2 + 12/y = 3Or, 12/y = 3-3/2Or, 12/y = 3/2Or, y = 8km/hrNow, velocity of stream = (x-y)/ 2= (12-8)/ 2 = 2km/hr.42 / 100 Category: Compound Interest QuestionsThe difference between simple interest and compound on Rs. 1200 for one year at 10% per annum reckoned half-yearly is: Rs. 3.75 Rs. 3 Rs. 4 Rs. 2.50 Answer: Option BExplanation:S.I. = Rs1200 x 10 x 1= Rs. 120.100C.I. = Rs.1200 x1 +52- 1200= Rs. 123.100 Difference = Rs. (123 - 120) = Rs. 3.43 / 100 Category: Number QuestionsWhat is the sum of all odd numbers up to 240? 14400 11400 12400 13400 Answer with explanation:Number of odd numbers up to 240 =240⁄2= 120Sum of first n odd numbers = n2n = 120Required sum = 1202 = 1440044 / 100 Category: Compound Interest QuestionsIf the difference between Simple Interest and Compound Interest on a sum of money for 3 years is Rs. 200 and the rate of interest is 10%, what is the sum? Rs. 6451.6 Rs. 6151.6 Rs. 6351.6 Rs. 6251.6 Explanation:If the difference between C.I. and S.I. on a certain sum for 3 years at rate of interest r% is Rs. X, then the sum is given by;Sum = We have;X = Rs. 200r = 10%Therefore, sum = 45 / 100 Category: Number QuestionsThe sum of first n odd natural numbers is be given by: n2 – 1 n2 + 1 n2 (n+1)2 Answer with explanation:First n odd natural numbers are 1, 3, 5, 7, 9. (2n-1)The series of numbers is an arithmetic progression where the first term is 1 and the last term is 2n – 1.Apply formula; Sn =n⁄2( first term + last term)∴Sn =n⁄2[(1 + (2n – 1)]=n⁄2*2n = n246 / 100 Category: Average QuestionsThe captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team? 25 years 24 years 23 years 22 years Explanation:Let the average age of the whole team by x years. 11x - (26 + 29) = 9(x -1) 11x - 9x = 46 2x = 46 x = 23.So, average age of the team is 23 years.47 / 100 Category: Partnership QuestionsPraveen and Sunny enter into a partnership. Praveen puts in Rs. 50 and Sunny put in Rs. 45. At the end of 4 months Praveen withdraws half of his capital, and at the end of 6 months, Sunny withdraws half of his capital. Ashu Bhati then enters with a capital of Rs. 70. At the end of 12 months, in what ratio will the profit be divided? 65:32:56 84:82:80 80:81:84 54:60:66 Explanation:Let Praveen’s capital is C1 = 50 for period T1= 4 months, and C11= 25 for period T11= 8Sunny’s capital is C2 = 45 for period T2 = 6 months, and C22 = 45/2 for period T22= 6 months.Ashu Bhati’s capital is C3 = 70 for period T3 = 6 months.Now, apply the profit ratio formula:(C1 * T1): (C2 * T2): (C3 * T3) = p1: p2: p3But here we have 2 different values for Praveen and Sunny.So, (C1 * T1 + C11 * T11): (C2 * T2 + C22 * T22): (C3 * T3) = p1: p2: p3Now, (50*4 + 25*8): (45*6 + (45*2)/6): (70*6) = p1: p2: p3The ratio of their profit is p1: p2: p3 = 400: 405: 420Divide all ratios by 25.Hence, the ratio will be 80: 81: 8448 / 100 Category: Average QuestionsIf the average of three consecutive even numbers is 34, find the largest of these numbers. 30 34 36 32 Explanation:Let the first number is X, then the next two even numbers would be X+2, X+4As per question; = 34 = 343X + 6 = 1023X = 96X = 32Largest number would be = 32 + 4 = 3649 / 100 Category: Ages QuestionsSimran is younger than Simarjeet by 7 years, and the ratio of their ages is 7:9. What is the age of Simran? 24 years 25.5years 24.5 years 23.5 years Explanation:Let the age of Simran and Simarjeet be 7x and 9x respectivelyAccording to the Question-7x=9x-7x=7/2=3.5So, Simran’s age =7x=7×3.5=24.5 years.50 / 100 Category: Ages QuestionsThe product of the ages of Shyam and Ram is 240. If double the age of Ram is more than Shyam’s age by 4 years, what is Ram’s present age? 16 years 14 years 12 years 10 years Explanation:: Let the age of Ram = X yearsAge of Shyam = Y yearsAccording to questionXY= 240 …………eq.1And, 2X = Y + 4Y= 2X- 4Y = 2(X-2) ……………eq.2Now putting the value of eq.2 in eq.1X ×[ 2(X-2)] = 240X × (2X – 4) =2402X2 – 4X =240X2– 2X = 120X2 – 2X – 120 = 0Doing the factors of above equation:X2 – (12-10)X – 120 = 0X2 -12X + 10X -120 = 0X(X-12) + 10(X-12) = 0(X-12) (X+10) = 0X+10 = 0, X-12 = 0X= -10, X = 12Therefore Ram’s age is 12 years.51 / 100 Category: Percentage QuestionsThe population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is: 4.37% 5% 6% 8.75% Explanation:Increase in 10 years = (262500 - 175000) = 87500.Increase% =87500x 100% = 50%.175000 Required average =50% = 5%.1052 / 100 Category: Compound Interest QuestionsThe simple interest on a certain sum of money at rate of interest 5% per annum for 2 years is Rs. 500. What is the compound interest on the same sum for the same period and at the same rate of interest? Rs.412.5 Rs.400 Rs.512.5 Rs.500 Explanation:S.I. = 500r = 5%t = 2 yearsBefore finding C.I. we have to find the sum or principal;Apply formula; Principal = Principal = = Rs. 5000Now we have to find the Amount;Apply formula; Amount =Amount = 5000 = 5000 * 1.05 * 1.05 = Rs. 5512.5C.I. = Amount – PrincipalC.I. = 5512.5 – 5000 = Rs. 512.5 (Option D)53 / 100 Category: Clock QuestionsAn accurate clock indicates 8 O’ clock in the morning. Through how many degrees the hour hand turns when the clock indicates 3 O’ clock in the afternoon? 225° 150° 270° 210° Explanation:There are 7 hours between 8 O’ clock in the morning and 3 O’ clock in the afternoon.Now, angle traced by the hour hand in 12 hours = 360°∴ Angle traced by the hour hand in 7 hours =54 / 100 Category: Calender QuestionsWhat was the day of the week on 17th June, 1998? Tuesday Thursday Wednesday Monday Explanation:17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)Odd days in 1600 years = 0Odd days in 300 years = (5 x 3) 197 years has 24 leap years + 73 ordinary years.Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days 168 days = 24 weeks = 0 odd day.Total number of odd days = (0 + 1 + 2 + 0) = 3.Given day is Wednesday.55 / 100 Category: Boats and Stream QuestionsSpeed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph. A man rows to a place at a distance of 105 km and comes back to the starting point. The total time taken by him is: 28 hours 20 hours 16 hours 24 hours Explanation:Speed upstream = 7.5 kmph.Speed downstream = 10.5 kmph. Total time taken =105+105hours = 24 hours.7.510.556 / 100 Category: Boats and Stream QuestionsA man can row 9[1/3] km/hr in still water. He finds that it takes thrice as much time to row upstream as to row downstream (same distance). Find the speed of the current. 3[1/3] km/hr 4[2/3] km/hr 3[1/9] km/hr 1[1/4] km/hr Answer with the Explanation:The speed of man in still water is 9[1/3]ATQ, time taken while rowing upstream = 3kTime taken while rowing downstream = kWe know that time is inversely proportional to speed.Upstream speed (y) = kDownstream (x) = 3kNow, apply the formula.Speed of man in still water = (1/2) [speed of downstream + speed of upstream]Or, 9[1/3] = (1/2) [3k+ k]Or, 28/3 = 2kOr, k = 14/3So, upstream speed (y) = 14/3And, downstream speed (x) = (14/3) * 3 = 14Now, apply the formula.Speed of current = (1/2) [downstream speed – upstream speed]= (½) [14 – 14/3]= 28/6 = 4[2/3]57 / 100 Category: Ages QuestionsVipul’s present age is two-fifths of the age of his mother. After 8 years, Vipul will be one-half of the age of his mother. What is the present age of Vipul’s mother? 40 Years 60 Years 30 Years 50 Years Solution:Let the present age of the Vipul =xThen, the present age of the mother Given that, after 8 years, Vipul’s will be one-half of the age of his mother.X=16So, the present age of the mother:58 / 100 Category: Clock QuestionsA watch which gains uniformly is 5 minutes slow at 6am on Monday and is 5 minutes 48 seconds fast at 6pm on the following Monday. When was it correct? 5:20 pm on Wednesday 5:20 pm on Thursday 4:20 pm on Wednesday 4:20 pm on Thursday Explanation:Time from 6am on Monday to 6pm on following Monday = 7 days and 12 hours, i.e. 24*7 + 12 = 180 hoursSo, the watch gains minutes in 180 hoursNow, minutes are gained in 180 hours∴ 5 minutes will be gained in hours or 83 hours 20 minutes.83 hour 20 minutes = 3 days (72 hours) 11 hours 20 minutesTherefore, the watch was correct 3 days 11 hours 20 minutes after 6am on Monday, i.e. it was correct at 20 minutes past 5pm on Thursday.59 / 100 Category: Boats and Stream QuestionsA man covers a distance of 36 km in 6 hours downstream and a distance of 40 km upstream in 8 hours. What is his speed in still water? None of these 7km/hr 5.5km/hr 8km/hr Answer with the Explanation:Upstream speed = distance covered in upstream/ timeDownstream speed = distance covered in downstream/ timeUpstream speed = 40/8 = 5kmphDownstream speed = 36/6 = 6kmphNow, speed of man in still water= (½) [speed in downstream + speed in upstream]Or, the speed of man = [½][6+5] =5.5kmph60 / 100 Category: Calender QuestionsIf it was Wednesday on March 1, 2006, which day was it on March 1, 2002? Friday Tuesday Sunday Monday Explanation: Total number of odd days between the years 2002 and 2006 =(2006 – 2002) + 1 = 5 odd days. The year 2004 is a leap year, it has two odd days. So, one extra odd day is added.So, if it was Wednesday on March 1, 2006, it would be (Wednesday – 5) Friday on March 1, 2002.61 / 100 Category: Height and Distance QuestionsA storm breaks a tree. The broken part of tree bends so that the top of the tree touches the ground and makes an angle of 60° with the horizontal plane. If the distance between the base of the tree and the point where top of tree touches the ground is 10 m, find the height of the tree? 17.3 m 20.3 m 37.3 m 27.3 m Answer with explanation:PQ = 10 and let RQ be X.X = 10 √3Now, PR2 = X2 + (10)2PR2 = (10 √3)2 + (10)2= 300 + 100PR2 = 400PR = 20Height of tree = RQ + PR= X + 20= 10 √3 + 20= 10 * 1.73 + 20= 17.3 + 20= 37.3 meter (Option A)62 / 100 Category: Average Questions10 typists can type 600 pages in 8 hours.Find the average number of pages typed by each typist in an hour. 8 pages 7 pages 7.5 pages 8.5 pages The correct answer is BExplanation:Total pages typed by 10 typists in 8 hours = 600Pages typed by one typist in 8 hours = = 60 pagesPages typed by one typist in one hour = = 7.5 pages63 / 100 Category: Average QuestionsA family consists of two grandparents, two parents and three grandchildren. The average age of the grandparents is 67 years, that of the parents is 35 years and that of the grandchildren is 6 years. What is the average age of the family? 28(4/7) Years 33(3/7) Years 32(4/7) Years 31(5/7) Years Required average=67 x 2 + 35 x 2 + 6 x 32 + 2 + 3=134 + 70 + 187=2227= 315years.764 / 100 Category: Boats and Stream QuestionsA man rows to a place 48 km distant and come back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is: 2.5 km/hr 1 km/hr 1.5 km/hr 2 km/hr Explanation:Suppose he move 4 km downstream in x hours. Then,Speed downstream =4km/hr.xSpeed upstream =3km/hr.x48+48= 14 or x =1.(4/x)(3/x)2So, Speed downstream = 8 km/hr, Speed upstream = 6 km/hr.Rate of the stream =1(8 - 6) km/hr = 1 km/hr.265 / 100 Category: Percentage QuestionsIn an examination, 25% candidates failed in English and 35 % students failed in Math.If 15 % candidates failed in both, what is the percentage of candidates who passed in both the subjects? 58 % 50 % 45 % 55 % Explanation:Apply formula: = 100 – (x + y – z)x = 25%y = 35 %z = 15 %∴ Required percentage of candidates = 100 – (25 + 35 – 15)= 100 – 45 = 55%66 / 100 Category: Boats and Stream QuestionsA boat travels upstream from Q to P and downstream from P to Q in 3 hours. If the distance between P to Q is 4km and the speed of the stream is 1kmph, then what is the velocity of the boat in still water? 4 kmph 2 kmph 3 kmph 5 kmph Answer with the Explanation:Let the velocity or speed of the boat in still water is x km/hr.And the Speed of the stream = 1km/hrSo, the speed of the boat along the stream = (x+1) km/hr.The speed of the boat against the stream = (x-1) km/hr.Note: time = Distance / SpeedSo, [4/ (x+1)] + [4/ (x-1)] = 3 hrs.Note: go through the given options to get the answer quickly or solve the equation as follows:Or, [4 (x+1+x-1)]/ [(x+1) (x-1)] = 3Or, 8x = 3(x2-12)Or, 8x = 3×2-3Or, 3×2-8x-3=0Or, 3×2- 9x+ x-3 = 0Or, (x-3) (3x+1) = 0Therefore x=3 or, x=-1/3 (speed can’t be -ve)Hence, the speed or velocity of the boat in still water is 3 km/hr.67 / 100 Category: Number QuestionsWhich of the following is the result of 1505 x 1505? 2265015 2265045 2265025 2265035 Answer with explanation:Apply formula; (a + b)2 = a2 + b2 + 2ab1505 x 1505=15052= (1500 + 5)2=15002 + 52 + 2 *1500* 5= 2250000 + 25 + 15000= 2265025Solve more problems on numbers.68 / 100 Category: Number Questions5358 x 51 = ? 273258 273248 273268 273278 Explanation:5358 x 51= 5358 x (50 + 1)= 5358 x 50 + 5358 x 1= 267900 + 5358= 273258.69 / 100 Category: Boats and Stream QuestionsThe velocity of a boat in still water is 9 km/hr, and the speed of the stream is 2.5 km/hr. How much time will the boat take to go 9.1 km against the stream? 2hr. 48min 1hr. 24min 2hr. 40min 1 hr. 20min Answer with the Explanation:ATQ,Speed of boat in still water (Sb) = 9km/hr Speed of stream (Sc) = 2.5km/hr Distance against the stream = 9.1 kmNote: against the steam = upstreamNow, apply the formula:The speed of boat upstream = speed of boat – the speed of the streamThe speed of upstream = 9-2.5 = 6.5km/hr Now, time= Distance/speed Time = 9.1/6.5, or 7/5 Or, time = 1[2/5] Or, 1hr + (2/5)*60 = 1hr + 24minutes70 / 100 Category: Percentage QuestionsOn increasing the price of tickets for a show by 20 % the audience decreases by 30%. What is the effect on revenue? 16% increase 16% decrease 4% decrease 4% increase Explanation:Apply formula: Effect on revenue= percent increase – percent decrease –= 20 – 30 –= – 10 –= -10 – 6 = – 16 %‘-‘ sign shows decrease in revenue.71 / 100 Category: Calender QuestionsWhat was the day of the week on 28th May, 2006? Sunday Friday Thursday Saturday Explanation:28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)Odd days in 1600 years = 0Odd days in 400 years = 05 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd daysJan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days 148 days = (21 weeks + 1 day) 1 odd day.Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.Given day is Sunday.72 / 100 Category: Height and Distance QuestionsThe tops of two poles are connected by a wire. The heights of the poles are 10 m and 14 m respectively. If the wire makes a 30° angle with the horizontal, find the length of the wire? 8.5 m 7 m 7.5 m 8 m Answer with explanation:Let AD and BE, be the poles of height 10 m and 14 m respectively.DE is the wire of length = LDC is parallel to AB so AD = BC = 10 mSo, CE = BE – BC = 14 – 10 = 4 m73 / 100 Category: Boats and Stream QuestionsA boat covers a certain distance downstream in 1 hour, while it comes back in 1 hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water? 13 kmph 15 kmph 12 kmph 14 kmph Explanation:Let the speed of the boat in still water be x kmph. Then,Speed downstream = (x + 3) kmph,Speed upstream = (x - 3) kmph. (x + 3) x 1 = (x - 3) x32 2x + 6 = 3x - 9 x = 15 kmph74 / 100 Category: Ages QuestionsQ is as much younger than R as he is older than T. If the sum of the ages of R and T is 50 years, what is definitely the difference between R and Q's age? 1 year 25 year Data inadequate 2 year Explanation:Given that:1. The difference of age b/w R and Q = The difference of age b/w Q and T.2. Sum of age of R and T is 50 i.e. (R + T) = 50.Question: R - Q = ?.Explanation:R - Q = Q - T(R + T) = 2QNow given that, (R + T) = 50So, 50 = 2Q and therefore Q = 25.Question is (R - Q) = ?Here we know the value(age) of Q (25), but we don't know the age of R.Therefore, (R-Q) cannot be determined.75 / 100 Category: Number QuestionsThe sum of first 45 natural numbers is: 2070 2140 1035 1280 Explanation:Let Sn =(1 + 2 + 3 + ... + 45). This is an A.P. in which a =1, d =1, n = 45.Sn =n[2a + (n - 1)d]=45x [2 x 1 + (45 - 1) x 1]=45x 46= (45 x 23)222= 45 x (20 + 3)= 45 x 20 + 45 x 3= 900 + 135= 1035.Shorcut Method:Sn =n(n + 1)=45(45 + 1)= 1035.2276 / 100 Category: Compound Interest QuestionsSimple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on Rs. 4000 for 2 years at 10% per annum. The sum placed on simple interest is: Rs. 2000 Rs. 1750 Rs. 1650 Rs. 1550 Explanation:C.I.= Rs.4000 x1 +102- 4000100= Rs.4000 x11x11- 40001010= Rs. 840. Sum = Rs.420 x 100= Rs. 1750.3 x 877 / 100 Category: Ages QuestionsSachin is younger than Rahul by 7 years. If their ages are in the respective ratio of 7 : 9, how old is Sachin? 24.5 years 20 years 25 years 16 years Explanation:Let Rahul's age be x years.Then, Sachin's age = (x - 7) years.x - 7=7x9 9x - 63 = 7x 2x = 63 x = 31.5Hence, Sachin's age =(x - 7) = 24.5 years.78 / 100 Category: Number Questions72519 x 9999 = ? 725117481 725117371 725117261 725117591 Explanation:72519 x 9999= 72519 x (10000 - 1)= 72519 x 10000 - 72519 x 1= 725190000 - 72519= 725117481.79 / 100 Category: Clock QuestionsThe angle between the minute hand and the hour hand of a clock when the time is 8.30, is: 75° 60° 90° 80° Angle traced by hour hand in17hrs =360x17°= 255°.2122Angle traced by min. hand in 30 min. =360x 30°= 180°.60 Required angle = (255 - 180)° = 75°.80 / 100 Category: Percentage QuestionsTwo tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? None of these Rs. 300 Rs. 250 Rs. 200 Explanation:Let the sum paid to Y per week be Rs. z.Then, z + 120% of z = 550. z +120z = 55010011z = 5505 z =550 x 5 = 250.1181 / 100 Category: Clock QuestionsHow much does a watch lose per day, if its hands coincide every 63 minutes? 54min 55min 57min 56min Explanation:|The hands of a clock coincide once after 65 minutes in every hour.As per question, the hands coincide in every 63 minutes.Therefore, the loss in 63 minutes = Now, loss in 63 minutes = ∴ Loss per day or in 24 hours=82 / 100 Category: Number QuestionsIf two-third of three-fourth of a number is 34, find the 20% of that number? 14.6 13.6 13 14 Answer with explanation:Let the number is X.As per question;83 / 100 Category: Percentage QuestionsIf A’s income is 12 % more than B’s income, B’s income is how much less than A’s income? 11.7% 10.7% 9.7% 10.7% Explanation:Apply formula;r = 12 %84 / 100 Category: Partnership QuestionsAman started a business investing Rs. 70,000. Rakhi joined him after six months with an amount of Rs.. 1,05,000 and Sagar joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business? 12 : 15 : 16 9 : 7 : 13 7 : 6 : 10 42 : 45 : 56 Explanation:Aman : Rakhi : Sagar = (70,000 x 36) : (1,05,000 x 30) : (1,40,000 x 24) = 12 : 15 : 16.85 / 100 Category: Number QuestionsThe difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ? 240 295 300 270 Explanation:Let the smaller number be x. Then larger number = (x + 1365). x + 1365 = 6x + 15 5x = 1350 x = 270Smaller number = 270.86 / 100 Category: Ages QuestionsThe present ages of Arun, Sunil, and Vivek are in proportions 4:7:9. Before eight years, the sum of their ages was 56. What are their present ages in years? 16,28,40 16,30,40 16,30,36 16,28,36 Explanation:Let the ratio constant be xThen the Present age of Arun, Sunil and Vivek would be 4x, 7x, 9xAge before eight years:4x-8, 7x-8, 9x-8According to question4x-8 + 7x-8 + 9x-8 = 5620x = 80x= 80/20x= 4Then their present is 4×4 = 16; 7×4= 28 and 9×4= 36 respectively.87 / 100 Category: Number QuestionsThe smallest 3 digit prime number is: 109 103 113 101 Explanation:The smallest 3-digit number is 100, which is divisible by 2. 100 is not a prime number.101 < 11 and 101 is not divisible by any of the prime numbers 2, 3, 5, 7, 11.101 is a prime number.Hence 101 is the smallest 3-digit prime number.88 / 100 Category: Average QuestionsThe average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person? 76 kg 82 kg 85 kg 80 kg Explanation:Total weight increased = (8 x 2.5) kg = 20 kg.Weight of new person = (65 + 20) kg = 85 kg.89 / 100 Category: Height and Distance QuestionsThe angle of elevation of the top of an unfinished building at point P which is 120 m away from its base is 30°. If the angle of elevation of the finished building at the same point would be 60°, find the height of the remaining part of the building. 80 √3 m 70 √3 m 85 √3 m 75 √3 m Answer with explanation:Let the height of remaining part of building be X.then,120 + √3 X = 120*3120 + √3 X = 360√3 X = 360 – 120√3 X = 24090 / 100 Category: Height and Distance QuestionsThe angle of elevation of the sun, when the length of the shadow of a tree square root of 3 times the height of the tree, is: 90° 30° 45° 60° Explanation:Let AB be the tree and AC be its shadow.Let ACB = .Then,AC=3 cot = 3AB = 30°.91 / 100 Category: Number QuestionsA boy was asked to multiply a number by 25 but by mistake he multiplied by 45 and the answer was 200 more than the correct answer. What was the number? 7 12 8 10 The Correct answer is (C)Answer with explanation:92 / 100 Category: Ages QuestionsSix years ago the ratio of the ages of Preeti and Ruchi was 6: 5. After four years the ratio of their ages will be 11: 10. What is Ruchi’s present age? 15 years 18 years 16 years 17 years Explanation:The ratio of the ages of Preeti and Ruchi six years ago =6:5According to Question:six years ago the age of Preeti=6xSix years ago age of Ruchi=5xafter 4years, the ratio of their ages =11:10(6x+10):(5x+10)=11:1010(6x+10) =11(5x+10)60x + 100 = 55x + 1105x=10x=10/5=2Ruchi’s present age=(5x+6)=5×2+6=16 years93 / 100 Category: Height and Distance QuestionsThe top of a 30 m high wall makes an angle of elevation of 60° with the top of a tower and makes an angle of depression of 45° with the bottom of the tower. Find the distance between tower and wall? 30 m 27.5 m 28 m 29 m Answer with explanation:Let AD is the wall of height 30 m and BE is the tower and X be the distance between tower and wall.X = 30 m (Option D)94 / 100 Category: Compound Interest QuestionsThe difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. What is the rate of interest per annum? 8 7 12 10 Explanation:15000 x1 +R2- 15000-15000 x R x 2= 96100100 150001 +R2- 1 -2R= 96100100 15000(100 + R)2 - 10000 - (200 x R)= 9610000 R2 =96 x 2= 643 R = 8. Rate = 8%.95 / 100 Category: Clock QuestionsAt what times between 5 O’ clock and 6 O’ clock the hands of a clock are 10 minute spaces apart? 16(4/11)min. past 5 ,38(2/11)min. past 5 16(4/11)min. past 5 ,38(2/11)min. past 5 18(4/11)min. past 5 ,36(2/11)min. past 5 16(4/11)min. past 5 ,38(2/11)min. past 5 Explanation:Between 5 O’ clock and 6 O’ clock, the hands will be 10 minutes spaces apart twice, i.e. when the minute hand is 10 minute spaces behind the hour hand and when the minute hand is 10 minute space ahead of the hour hand.Case 1: When the minute hand is 10 minutes spaces behind the hour hand;At 5 O’ clock, the minute hand is 25 minute spaces behind the hour hand.So, the minute hand has to gain (25-10) = 15 minute spaces over hour hand to be 10 minute spaces apart.Now, 55 minute spaces are gained in 60 minutes.15 minute spaces will be gained in * 15 = 16 minutes∴The hands of the clock will be 10 minute spaces apart at 16 minutes past 5.Case 2: When the minute hand is 10 minute spaces ahead of the hour hand.The minute hand has to gain (25 + 10) = 35 minute spaces over the hour hand.Now, 55 minutes are gained in 60 minutes.35 minutes will be gained in * 35 = 38 minutes∴ The hands of the clock will be 10 minute spaces apart at 38 minutes past 5.96 / 100 Category: Calender QuestionsIt was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010? Sunday Friday Tuesday Wednesday Explaination:On 31st December, 2005 it was Saturday.Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days. On 31st December 2009, it was Thursday.Thus, on 1st Jan, 2010 it is Friday.97 / 100 Category: Average QuestionsAverage age of a group of 30 boys is 16 years. A boy of age 19 leaves the group and a new boy joins the group. If the new average age of the group is 15.8 years, find the age of the new boy. 14 years 13 years 12 years 15 years Explanation:Let the age of new boy = X yearsTotal age of 30 boys = 30*16 = 480 yearsAs per question, if we minus age of boy who leaves the group and then add the age of boy who joins the group the new average becomes = 15.8 years.∴ = 15.8480 – 19 + X = 474X = 474 – 480 +19X = – 6 +19= 13 yearsTry to solve more problems on average.98 / 100 Category: Clock QuestionsA watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was it correct? 2 p.m. on Tuesday 2 p.m. on Wednesday 3 p.m. on Thursday 1 p.m. on Friday Explanation:Time from 12 p.m. on Monday to 2 p.m. on the following Monday = 7 days 2 hours = 170 hours. The watch gains2 + 44min.or34min. in 170 hrs.55Now,34min. are gained in 170 hrs.5 2 min. are gained in170 x5x 2hrs= 50 hrs.34 Watch is correct 2 days 2 hrs. after 12 p.m. on Monday i.e., it will be correct at 2 p.m. on Wednesday.99 / 100 Category: Calender QuestionsOn what dates of April, 2001 did Wednesday fall? 2nd, 9th, 16th, 23rd, 30th 3rd, 10th, 17th, 24th 4th, 11th, 18th, 25th 1st, 8th, 15th, 22nd, 29th Explanation:We shall find the day on 1st April, 2001.1st April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001)Odd days in 1600 years = 0Odd days in 400 years = 0Jan. Feb. March April(31 + 28 + 31 + 1) = 91 days 0 odd days.Total number of odd days = (0 + 0 + 0) = 0On 1st April, 2001 it was Sunday.In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.100 / 100 Category: Average QuestionsA grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500? Rs. 4991 Rs. 5991 Rs. 3991 Rs. 6991 Explanation:Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009. Required sale = Rs. [ (6500 x 6) - 34009 ]= Rs. (39000 - 34009)= Rs. 4991. NameEmail Your score isThe average score is 6% LinkedIn Facebook Twitter VKontakte 0% Restart quiz Exit Satisfied with our quiz?Leave us a review Send feedback